-4x^2=-38

Solution for -4x^2=-38 equation:

-4x^2=-38

We move all terms to the left:

-4x^2-(-38)=0

We add all the numbers together, and all the variables

-4x^2+38=0

a = -4; b = 0; c = +38;
Δ = b2-4ac
Δ = 02-4·(-4)·38
Δ = 608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{608}=\sqrt{16*38}=\sqrt{16}*\sqrt{38}=4\sqrt{38}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{38}}{2*-4}=\frac{0-4\sqrt{38}}{-8}
=-\frac{4\sqrt{38}}{-8}
=-\frac{\sqrt{38}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{38}}{2*-4}=\frac{0+4\sqrt{38}}{-8}
=\frac{4\sqrt{38}}{-8}
=\frac{\sqrt{38}}{-2}
$